Or at least make it the equivalent proportionately.
A little work on google found me this:
I didn't double check the math.
Let's account for the fact that an nhl puck is actually 7.065 square inches you have 24 feet opening to score on, which in inches is 3456 sq. inches, 7.065/3456 = .002 which is .2% of the available space to score. now assuming your soccer ball is a size 5 that would be 68-70 cm, so A = 4πr^2 (1,156 cm) = 14,527 sq cm and a soccer net opening is 222967 cm square x 7432.24 cm square = 1657144256.08 cm square. 14,527/1,657,144,256.08 = .0009, so .09%
Edit: typo, and I am dumb
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